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Question #260

Author: admin
tags: Go   
package main

import "fmt"

func main() {
	x := 5
	defer fmt.Println(x)              // ??
	defer func() { fmt.Println(x) }() // ??
	x = 10
}
What will be printed?
5, 5
5, 10
10, 5
10, 10
Quote from the "The Go Programming Language Specification":
Each time a "defer" statement executes, the function value and parameters to the call are evaluated as usual and saved anew but the actual function is not invoked. Instead, deferred functions are invoked immediately before the surrounding function returns, in the reverse order they were deferred.
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